4y^2-8=2y^2

Solution for 4y^2-8=2y^2 equation:

Simplifying
4y2 + -8 = 2y2

Reorder the terms:
-8 + 4y2 = 2y2

Solving
-8 + 4y2 = 2y2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y2' to each side of the equation.
-8 + 4y2 + -2y2 = 2y2 + -2y2

Combine like terms: 4y2 + -2y2 = 2y2
-8 + 2y2 = 2y2 + -2y2

Combine like terms: 2y2 + -2y2 = 0
-8 + 2y2 = 0

Add '8' to each side of the equation.
-8 + 8 + 2y2 = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 2y2 = 0 + 8
2y2 = 0 + 8

Combine like terms: 0 + 8 = 8
2y2 = 8

Divide each side by '2'.
y2 = 4

Simplifying
y2 = 4

Take the square root of each side:
y = {-2, 2}